the sum of first 3 terms of ap is 24 and sum of their square is 224. find first 3 terms
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let (a-d) ,a,a+d be the three terms in AP
according to the question
a-d+a+a+d= 24
3a=24
a=8
sum of the sq of these 3 terms
(a-d)^2+(a^2)+(a+d)^2=224
a^2+d^2-2ad+a^2+a^2+d^2+2ad=224
3a^2+2d^2=224________(1)
putting the value of a in eq 1 we get
d=plus or minus 4
thus the terms are 12,8,4 or 4,8,12
let (a-d) ,a,a+d be the three terms in AP
according to the question
a-d+a+a+d= 24
3a=24
a=8
sum of the sq of these 3 terms
(a-d)^2+(a^2)+(a+d)^2=224
a^2+d^2-2ad+a^2+a^2+d^2+2ad=224
3a^2+2d^2=224________(1)
putting the value of a in eq 1 we get
d=plus or minus 4
thus the terms are 12,8,4 or 4,8,12
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