The sum of first 3 terrms of an A.P is 42 and the product of the first term and last term is 52.Find the first term and common difference.
Answers
Answered by
0
Let a-d , a, a+ d are in AP
ATQ,
(a-d)+a+(a+d)=42
3a= 42
a= 14
again
(a-d)(a+d)=52
= 52
14²-d²=52
d²=196-52=144
d= ±12
hence, first term is (a - d) = 2 [ when d = 12 ] and 26 [ when d = -12 ]
so, first term, a = 2 when common difference, d = 12
first term, a = 26 when common difference , d = -12
Similar questions