the sum of first 4 terms of an ap is 38 and the product of second and third term is 88 find the terms
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let terns be a-d, a, a+d,a+2d
sum:4a+2d=38
2a+d=19
Now (a-d)(a+d)=88
Now put d=19-2a in above eqn... u will get a,, then find d... and then u"ll get numbers
sum:4a+2d=38
2a+d=19
Now (a-d)(a+d)=88
Now put d=19-2a in above eqn... u will get a,, then find d... and then u"ll get numbers
saurabhsemalti:
why?
Answered by
1
Here your question wrong 4 is sum here no. InAp. Then (a-3d),(a-d), ( a+d), (a+3d) put on if
This your. Right question then follow question
And after that elimination apply on this question. a+3d=38,(a+d) (a+2d)=84
This your. Right question then follow question
And after that elimination apply on this question. a+3d=38,(a+d) (a+2d)=84
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