The sum of first 45 natural numbers is:
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Answered by
44
sum of first n natural numbers = n(n+1)/2
sum of first 45 natural numbers = 45(45+1)/2
= 45*46/2
=45*23
= 1035
sum of first 45 natural numbers = 45(45+1)/2
= 45*46/2
=45*23
= 1035
Answered by
8
Answer:
Hey buddy here's your answer
n(n+1)/2
It's formula to find natural no.
45(45+1)/2
45(46)/2
2070/2
1035 Answer.
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