Question

The sum of first 45 terms of an A.P. is 3195 find the 23 term

Answer 1

Answer:

s45=3195

Sn=n/2(2a+(n-1)d)

s45=45/2(2a+44*d)

3195*2/45=2a+44d

2(a+22d)=71*2

a+22d=71*2/2

a+22d=71..........(1)

Now, to find 23 term

a23=a+(n-1)d

a23=a+(23-1)d

a23=a+22d

a23=71..............from eq(1)