Question

The sum of first 5 terms of an arithmetic sequence is 60. Find the middle term? Write the sequence?

Answer 1

Step-by-step explanation:

Let the terms of AP be

A−2d,a−d,a,a+d,a+2d

A/Q

(a−2d)+(a−d)+a+a(a+d)+(a+2d)=60

5a=60⇒a=12

and a×(a+d)=172+a+2d

⇒a

2

+ad=172+a+2d

⇒144+12d=172+12+2d

⇒12d−2d=184−144=40

⇒10d=40⇒d=4

∴a=12,d=4

and the terms are

12−4×2,12−4,12,12+4,12+2×4

=4,8,12,16,20