Math, asked by balajik830, 1 year ago

The sum of first 50 natural number(1+2+3+4+....... +50) is

Answers

Answered by kumar42108

1

Sn=n/2(2a+(n-1)d)

S50=50/2(2*1+(50-1)*1)

S50=25(2+49)

S50=25*51

S50=1275

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