The sum of first 50 terms of ap 8,12,16,is how much more than the sum of first 50 terms of ap 7,10,13
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1st AP sequence is
8,12,16....
a = 8
d = 4
N = 50
Last term of this sequence is
l = a + (n-1)d
l = 8+ (50 -1) 4
l = 8 + 49(4)
l = 8 +196
l = 204
So,
Sn = n/2 ( a+l )
Sn = 50/2( 8+ 204)
Sn = 25( 212)
Sn = 5300
2nd sequence of AP
7,10,13.....
a= 7
d= 3
N = 50
last term = a+49d
l = 7 + 49(3)
l = 154
Sn = 25(7+154)
Sn = 25 × 161
Sn = 4025
So , 1st sum of AP - 2nd sum of AP
= 5300 -4025
1275 is the answer
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