the sum of first 7term of an ap is 63 and sum of its next 7 term 161 find its 28term
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sum7 = 63
7/2 ( 2a + 6d) = 63
On solving the eq. will come like a+ 3d=9 .......eq 1
sum14 - sum7 = 161
sum14 - 63 = 161
sum14 = 224
14/2(2a + 13d) = 32
On solving , 2a + 13d =32 ......eq2
Now solve it simultaneously
eq2 - eq1
2a + 13d = 32
(a + 3d = 9)*2 = 2a + 6d = 18
-_____________
7d= 14
d=2
On putting the value of d,
a+3d = 9
a + 6 = 9
a = 3
term28 = a+ 27d
= 3 + 27*2
= 3 + 54
= 57
Hope it helps :)
7/2 ( 2a + 6d) = 63
On solving the eq. will come like a+ 3d=9 .......eq 1
sum14 - sum7 = 161
sum14 - 63 = 161
sum14 = 224
14/2(2a + 13d) = 32
On solving , 2a + 13d =32 ......eq2
Now solve it simultaneously
eq2 - eq1
2a + 13d = 32
(a + 3d = 9)*2 = 2a + 6d = 18
-_____________
7d= 14
d=2
On putting the value of d,
a+3d = 9
a + 6 = 9
a = 3
term28 = a+ 27d
= 3 + 27*2
= 3 + 54
= 57
Hope it helps :)
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