The sum of first 8 terms is 100 and sum of first 19terms is 551 find ap
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Answer:
Given,
s8=100;s19=551
Sn=n/2(2a+(n-1)d)
S8=4(2a+7d)=100
=>2a+7d=25
=>a=(25-7d)/2.........1
S19=19/2(2a+18d)=551
=>19(a+9d)=551
=>a+9d=29
=>(25-7d+18d)/2=29
=>25+11d=58
=>11d=33
=>d=3
Subs d in 1
a=(25-21)/2
a=2
Therefore ap= 2,5,8,....
Hpe it hlps u
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