The sum of first 9 term of an ap is 162. The ratio of its 6th term to its 13th term is 1:2. Find the first and fifteenth terms of an ap
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Answer:
a=6 and d=3
Step-by-step explanation:
S9=162
by solving this we get
a+4d=18.....1
we have given ,
T6/T13=1/2
a+5d/a+12d=1/2
2a+10d=a+12d
a=2d....2
from...1
2d+4d=18
6d=18
d=3
from...2
a=2(3)
a=6
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