the sum of first 9 terms of an ap is 351 and the sum of first 20 terms is 1770 find the 11th term
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Dear Student,
Sum of first 9 terms= 9/2[2a+(9-1)d]
351 = 9/2[2a+8d]
39 = a+4d.........(i)
Sum of first 20 terms = 20/2[2a+19d]
1770 = 20[2a+19d]
1770/20 = 2a+19d
88.5 = 2a+19d..............(ii)
Solving eq i and ii
2a+19d=88.5
a+4d=39
d=21/22 and a = 387/11
11 term=a+10d
=387/11+21/22*10
=984/22
Sum of first 9 terms= 9/2[2a+(9-1)d]
351 = 9/2[2a+8d]
39 = a+4d.........(i)
Sum of first 20 terms = 20/2[2a+19d]
1770 = 20[2a+19d]
1770/20 = 2a+19d
88.5 = 2a+19d..............(ii)
Solving eq i and ii
2a+19d=88.5
a+4d=39
d=21/22 and a = 387/11
11 term=a+10d
=387/11+21/22*10
=984/22
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