The sum of First 9terms of an AP is 351 and the sum of its 20thterm is 1770.find the number
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We know that the sum of 'n' numbers in AP
=>n/2[ 2a + (n - 1)d ]
where a = first Term of the series, n = no.of terms, d = Difference between terms
The sum of First 9terms of an AP is 351
=>9/2[ 2a + (9 - 1)d] = 351
=> 9[2a + 8d] = 351×2
=> 9[2a + 8d] = 702
=>(2a + 8d) = 702/9 = 78
=>2(a +4d) = 78
=>a + 4d = 78/2= 39
=>a + 4d = 39..(1)
=> a = 39 - 4d....(2)
The sum of its 20thterm is 1770
=>20/2[ 2a + (20 - 1)d ]= 1770
=>20[ 2a + 19d] = 1770×2
=> 40a + 380d = 3540
=>10(4a + 38d) = 10(354)
=>4a + 38d = 354
=> 2(2a + 19d) = 354
=> 2a + 19d = 354/2 = 177
=> 2a + 19d = 177 .....(3)
Now substitute (2) in (3)
2( 39 - 4d) + 19d = 177
78 - 8d +19d = 177
78 + 11d = 177
11d = 177 - 78
11d = 99
d = 99/11 = 9.
substitute 9 in (2)
a = 39 - 4(9)
a= 39 - 36 = 3.
a=3,d=9.
=>n/2[ 2a + (n - 1)d ]
where a = first Term of the series, n = no.of terms, d = Difference between terms
The sum of First 9terms of an AP is 351
=>9/2[ 2a + (9 - 1)d] = 351
=> 9[2a + 8d] = 351×2
=> 9[2a + 8d] = 702
=>(2a + 8d) = 702/9 = 78
=>2(a +4d) = 78
=>a + 4d = 78/2= 39
=>a + 4d = 39..(1)
=> a = 39 - 4d....(2)
The sum of its 20thterm is 1770
=>20/2[ 2a + (20 - 1)d ]= 1770
=>20[ 2a + 19d] = 1770×2
=> 40a + 380d = 3540
=>10(4a + 38d) = 10(354)
=>4a + 38d = 354
=> 2(2a + 19d) = 354
=> 2a + 19d = 354/2 = 177
=> 2a + 19d = 177 .....(3)
Now substitute (2) in (3)
2( 39 - 4d) + 19d = 177
78 - 8d +19d = 177
78 + 11d = 177
11d = 177 - 78
11d = 99
d = 99/11 = 9.
substitute 9 in (2)
a = 39 - 4(9)
a= 39 - 36 = 3.
a=3,d=9.
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