Math, asked by ishikakaur599, 1 year ago

The sum of first five terms of the series 2,8,32....is

Answers

Answered by bhoomi81
16
2*4=8
8*4=32
32*4=128
128*4=512.
So, sum of the first five terms of the series is
2+8=10+32=42+128=170+512=682..
Do, the sum of the numbers in the sequence is 682.
please mark as brainliest

bhoomi81: is mine correct?
ammunazriya: no it's wrong
ammunazriya: it is 682
bhoomi81: why??
bhoomi81: thank u and suru
bhoomi81: i mean sorry
ammunazriya: it's ok
Answered by swethassynergy
2

The sum of first five terms of the series 2,8,32....is 511.50.

Given:

The series 2,8,32....

To Find:

The sum of first five terms of the series 2,8,32....

Step-by-step explanation:

Formula Used:

Sum of  the  geometric sequence =\frac{a(r^{n} -1)}{(r-1)}   ------- formula no.01.

Where

a =  first number

r=  common ratio

n=  number of terms

Solution:

As given,The series 2,8,32....

This series in the  geometric sequence.

a=2

r=\frac{8}{2} =4

n=5

Applying the formula no.01.

The sum of first five terms  the geometric sequence =\frac{2(4^{5} -1)}{(5-1)}

                                                                                         =\frac{2(1024-1)}{4}

                                                                                          =\frac{2\times 1023}{4}

                                                                                           =511.50

Thus,the sum of first five terms of the series 2,8,32....is 511.50.

3SPJ3

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