The sum of first four 2digit number.
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Answer:
46
Step-by-step explanation:
First four 2-digit number are 10, 11, 12, 13
The given series is an A.P.
first term (a) = 10
common difference (d) = 1
number of terms (n) = 4
Sum of n term = n/2 [2a+(n-1)d]
= 4/2 [ 20+(4-1)1]
= 2 [23]
= 46
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