Math, asked by deepika93, 1 year ago

the sum of first four multiple of 8 is

Answers

Answered by DonDj
11
HERE IS THE SOLUTION FOR YOUR QUESTION;

£ The AP is 8,16,24,32.

◆Given : a=8 , d=8 , l=32 , n=4.

◆To Find : Sn=?.


◆◆Solution◆◆

Sn=n/2(a+l)

=>Sn=4/2(8+32)

=>Sn= 2(40)

=>Sn=80.


◆◆So the Sum Of First Four Multiple Of 8 is 80◆◆



HOPE IT HELPS




DonDj: If it helped u plz mark it as brainlest
DonDj: & plz mark my answer as brainlest if it helped u
DonDj: By the way which class u
Answered by Arcel
19

The Sum Of First Four Multiples Of 8 Is 80.

Step-by-step explanation:

Given:

First Term (a) = 8

Common Difference (d) = 8

Last term = 8 * 4 = 32

The AP goes like 8,16,24,32......

To Find:

The sum of first four multiples of 8.

Calculating:

Sn = n / 2 (a + l)

= 4 / 2 (8 + 32)

= (2) (40)

= 80

Therefore, the sum of first four multiples of 8 is 80.

Similar questions