The sum of first four terms in AP is 36. and the product of first and fourth term is 45. find first four terms
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Answer:
t1+t2+t3+t4=36
let the 4 terms be
a-2d, a-d, a+d, a+2d
thus , a-2d+a-d+a+d+a+2d=36
4a=36
a=9
(a-2d)×(a+2d)=45
a²+2ad-2ad-4d²=45
a²-4d²=45
9²-4d²=45
4d²=81-45
d²=36/4
d²=9
d=3
thus the 4 terms are
a-2d,a-d,a+d,a+2d
putting values of a and d ,we get
3,6,12,15
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