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The sum of first four terms of an arithmetic sequence is 64 and sum of first 10 terms is 340.what is the sum of first and fourth terms of this sequence?​

Answers

Answered by chourasiaraj408
1

\large\underline{\sf{Solution-}}

Solution−

Let assume that

First term of an AP series be a and common difference of an AP series is d.

Wᴇ ᴋɴᴏᴡ ᴛʜᴀᴛ,

↝ Sum of n terms of an arithmetic progression is,

\begin{gathered}\begin{gathered}\red\bigstar\:\:{\underline{\orange{\boxed{\bf{\green{S_n\:=\dfrac{n}{2} \bigg(2 \:a\:+\:(n\:-\:1)\:d \bigg)}}}}}} \\ \end{gathered}\end{gathered}

S

n

=

2

n

(2a+(n−1)d)

Wʜᴇʀᴇ,

Sₙ is the sum of n terms of AP.

a is the first term of the sequence.

n is the no. of terms.

d is the common difference.

According to statement,

\rm \: S_4 = 64S

4

=64

\rm \: \dfrac{4}{2} \bigg(2a + (4 - 1)d \bigg) = 64

2

4

(2a+(4−1)d)=64

\rm \:2 \bigg(2a + 3d \bigg) = 642(2a+3d)=64

\rm\implies \:2a + 3d = 32 - - - - (1)⟹2a+3d=32−−−−(1)

According to statement again

\rm \: S_{10} = 340S

10

=340

\rm \: \dfrac{10}{2} \bigg(2a + (10 - 1)d\bigg) = 340

2

10

(2a+(10−1)d)=340

\rm \: 5 \bigg(2a + 9d\bigg) = 3405(2a+9d)=340

\rm\implies \:2a + 9d = 68 - - - - (2)⟹2a+9d=68−−−−(2)

On Subtracting equation (1) from equation (2), we get

\rm \: 6d = 366d=36

\rm\implies \:d = 6⟹d=6

On substituting the value of d = 6, in equation (1), we get

\rm \: 2a + 3 \times 6 = 322a+3×6=32

\rm \: 2a + 18 = 322a+18=32

\rm \: 2a = 32 - 182a=32−18

\rm \: 2a = 142a=14

\rm\implies \:a = 7⟹a=7

=a+(n−1)d

Wʜᴇʀᴇ,

aₙ is the nᵗʰ term.

a is the first term of the sequence.

n is the no. of terms.

d is the common difference.

Tʜᴜs,

\rm \: a_1 + a_4a

1

+a

4

\rm \: = \: a \: + \: a \: + \: (4 - 1)d=a+a+(4−1)d

\rm \: = \:2 a \: + \: 3d=2a+3d

\rm \: = \:2 \times 7\: + \: 3 \times 6=2×7+3×6

\rm \: = \: 14 + 18=14+18

\rm \: = \: 32=32

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

SHORT CUT TRICK

From equation (1), we have

\rm \: 2a + 3d = 322a+3d=32

can be further rewritten as

\rm \: a + a + 3d = 32a+a+3d=32

\rm\implies \:a_1 + a_4 = 32⟹a

1

+a

4

=32

So, Sum of first and fourth term is 32

Answered by Anonymous
2

Answer:

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