The sum of first n natural number is
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Answer:
(n)(n+1)/2
Step-by-step explanation:
the first n natural numbers are in A.P. with a1 is 1 and d is 1
Sn= n/2(2a+(n-1)d)
= n/2(2+n-1)
= n.(n+1)/2
Answered by
1
Answer:
Step-by-step explanation:
The series is like
1,2,3,4,5,6,,n
as we know,
this is an AP
so using the sum of AP
S = n/2 ( a + l )
S-sum of AP
n-total terms of AP
a-first term of AP
l-last term of AP
S = n/2 ( a+ l )
S= n/2 ( 1 + n) substitute all values
S = n ( n + 1 ) / 2 we get the equation
is the required equation
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