The sum of first n
natural numbers is [MP PET 1984; RPET 1995]
A) n\,(n-1) B) \frac{n\,(n-1)}{2} C) n\,(n+1) D) \frac{n\,(n+1)}{2}
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Hey mate !!
Here's your answer !!
We know that sum of terms of an AP has a formula as:
![S_{n} = n / 2 * [ 2a + ( n - 1 ) d ] S_{n} = n / 2 * [ 2a + ( n - 1 ) d ]](https://tex.z-dn.net/?f=+S_%7Bn%7D+%3D++n+%2F+2+%2A++%5B+2a+%2B+%28+n+-+1+%29+d+%5D)
So let's write the AP for the the natural numbers.
AP = 1, 2, 3, 4, 5 ......∞
Here,
a = 1
d = 1
n = n
So, The sum is as follows:
![S_{n} = n / 2 * [ 2 ( 1 ) + ( n - 1 ) * 1 ] S_{n} = n / 2 * [ 2 ( 1 ) + ( n - 1 ) * 1 ]](https://tex.z-dn.net/?f=+S_%7Bn%7D+%3D+n+%2F+2+%2A+%5B+2+%28+1+%29+%2B+%28+n+-+1+%29+%2A+1+%5D+)
[tex] S_{n} = n / 2 * [ 2 + n - 1 ] [/tex]

[tex]= S_{n} = n ( n + 1 ) / 2 = S_{n} = n^{2} + n /2 [/tex]
Hope my answer helped !!
Cheers !!
Here's your answer !!
We know that sum of terms of an AP has a formula as:
So let's write the AP for the the natural numbers.
AP = 1, 2, 3, 4, 5 ......∞
Here,
a = 1
d = 1
n = n
So, The sum is as follows:
[tex] S_{n} = n / 2 * [ 2 + n - 1 ] [/tex]
[tex]= S_{n} = n ( n + 1 ) / 2 = S_{n} = n^{2} + n /2 [/tex]
Hope my answer helped !!
Cheers !!
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