The sum of first n natural numbers is one fifth of the sum of their squares find n
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first we should know that
sum of first n natural no= n(n+1)/2
sum of the square of
first n natural no is = n(n+1)(2n+1) / 6
according to the question
n(n+1)/2 = n(n+1)(2n+1) / (5×6)
on solving the above eq you will get
N=7
if you like mark it brainliest answer
Happy to help!
sum of first n natural no= n(n+1)/2
sum of the square of
first n natural no is = n(n+1)(2n+1) / 6
according to the question
n(n+1)/2 = n(n+1)(2n+1) / (5×6)
on solving the above eq you will get
N=7
if you like mark it brainliest answer
Happy to help!
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