Question

The sum of first 'n' odd natural number is​

Answer 1

Answer:

The first n odd natural numbers are given by 1,3,5,7,9…… (2n – 1) and this forms an AP. The sum of first n odd natural numbers is n2.

Answer 2

Step-by-step explanation:

We know,

AP : 1,3,5,7,9,-----------'n' terms

where a = 1 ; d = 2 and n=n

=>  $S_{n}=\frac{n}{2}(2a+(n-1)d)=\frac{n}{2}(2(1)+(n-1)2)$

=>  $S_{n}=\frac{n}{2}(2+(n-1)2)=n(1+(n-1))$

Therefore Sum of 'n' odd numbers is  $n^2$

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