Question

The sum of first n odd natural numbers is
a. n²
b. n+1
c. 2n+1
d. n


Don't give USELESS and wrong answers......​

Answer 1

Answer:

$n^{2}$

Explanation:

Sum (S)= 1+3+5+7+9+...+ (2n-3) + (2n-1)

This forms an Arithmetic Progression, with:

first term, a = 1

last term, l = 2n-1

$S= \frac{n}{2}(a+l)=\frac{n}{2}(1+2n-1)=\frac{n}{2}(2n)=n^2$

Answer 2

Answer:

n^2

For eg :- 1 + 3 + 5 = 9

1, 3, 5 are 3 numbers.

So, 3^2 = 9

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