Question

the sum of first n odd no.s be 625 then write the value of n

Answer 1

here is your answer

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Answer 2

AP of first n numbers will be

= 1 , 3 , 5........

a = 1

d = 2

$625= \frac{n}{2} (2 \times 1 + (n - 1)2 \\ \\ 625 = \frac{n}{2} (2 + 2n - 2) \\ \\ 625 = \frac{n}{2} \times 2n \\ \\ 625 = {n}^{2} \\ \\ \sqrt {625}=n \\ \\ n = 25$