the sum of first n odd number is 225. find n.
Answers
Step-by-step explanation:
- Sn=n/2(a+l)
- 225=n/2(1+l)
l=an=a+(n-1)d
=1+(n-1)2
=1+2n-2
=2n-1
- 225=n/2(1+2n-1)
- 225*2=n(2n)
- 450=2n^
- 450/2=n^
- 225=n^
- root225
The value of n is 15.
Given:
Sum of n odd number is 225.
To find:
The value of n.
Solution:
Odd numbers are integers that are not divisible by 2, which means they cannot be divided evenly by 2. They are the opposite of even numbers, which are integers that can be divided evenly by 2. Odd numbers end in digits 1, 3, 5, 7, or 9.
Examples of odd numbers include 1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, and so on. The number of odd numbers is infinite. The sequence of odd numbers can be represented as 1, 3, 5, 7, 9, 11, 13, ...
The sum of the first n odd numbers can be represented by the formula n². In this case, we know that:
n² = 225
To find n, we can take the square root of both sides:
n = √225
n = 15
So, the value of n is 15.
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