The sum of first n positive intergers is given by Sn =? n^s=n(n+1)/2,sn=n^3 ,n^s=n^2,n^s=n^2+1
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Answer:
it is given by Sn=n/2(2a+(n-1)d)
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Step-by-step explanation:
Sn = n/2 × (2a+(n-1)d). or n/2 × (a + an)
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