The sum of first n term of an AP is given by s©n= 2n^2 + 3 n. Find the sixteenth term of the Ap
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Answer: 65
Step-by-step explanation:
please see the steps in the pics below
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Step-by-step explanation:
Putting n=1
Sn=2(1)^2 + 3(1)
Sn=2+3
Sn=5 ..........(sum of 1st term)
Putting n=2
Sn=2(2)^2 + 3(2)
Sn=8 + 6
Sn=14 .........(sum of 2 terms)
Putting n=3
Sn=2(3)^2 + 3(3)
Sn=18 + 9
Sn=27 ...........(sum of 3 terms)
Since sum of 2 terms is 14
5+a2=14
a2=9
a1=5
a2=a+(n-1)d
a2=5+(2-1)d
a2=5+d
9-5=d
4=d
a16=a+(16-1)d
a16=5+(15)4
a16=65
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