the sum of first n term of an ap is given by Sn= 2n^2 + 3 and find the 16 term of the AP
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Given as
sn=2n^2+3n
To find out we need to find first term and Common difference
Let n= 1
We got the first term a = 5
Now also put n=2
Since it's the sum of 2 term =14
2nd term = S2 - a
= 14 - 5
= 9
Now we have
a1 = 5 and a2 = 9
Now d = a2- a1
d = 9 - 5 = 4
Now 16th term
16th term =a+15d=5+15(4)=65
hope it helps you
Given as
sn=2n^2+3n
To find out we need to find first term and Common difference
Let n= 1
We got the first term a = 5
Now also put n=2
Since it's the sum of 2 term =14
2nd term = S2 - a
= 14 - 5
= 9
Now we have
a1 = 5 and a2 = 9
Now d = a2- a1
d = 9 - 5 = 4
Now 16th term
16th term =a+15d=5+15(4)=65
hope it helps you
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