the sum of first n term of an ap is given by Sn= 2n² + 3n. find the sixteenth term of the AP
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Sn = 2n^2 + 3n
S1 = 2 + 3 = 5
Therefore T1 = 5
S2 = 8 + 6 = 14
T2 = 14 - 5 = 9
d = 9 - 5 = 4
T16 = 5 + 15×4 = 5 + 60 = 65
S1 = 2 + 3 = 5
Therefore T1 = 5
S2 = 8 + 6 = 14
T2 = 14 - 5 = 9
d = 9 - 5 = 4
T16 = 5 + 15×4 = 5 + 60 = 65
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