the sum of first n term of an AP is given by Sn= 2n²+ 3n, find the sixteenth term of an AP,
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pratiksha49:
thank u so much friend
Its my work.
ok
Dear, mate when put n = 2 in sn u will get sum of ist two terms not sum of second alone
*you
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Heya!!!
Tn = Sn - Sn-1
Tn = 2n² + 3n - ( 2× ( n - 1 )² + 3 ( n - 1 )
=>
Tn = 3n + 4n - 2 - 3n + 3
=>
Tn = 4n + 1
=>
T16 = 4 × 16 + 1
=>
T16 = 65
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