Question

The sum of first n term of an AP is n^2 then find its 10th term​

Answer 1

Answer:

19

Step-by-step explanation:

Sum of n terms of an AP, Sn=n²

First term = S1=1

Sum of two terms, S2=2²=4

Second term=S2-S1=4-1=3

Common difference =d=3-1 =2

tenth term=a10=a+9d=1+9×2

=1+18

=19

So tenth term is 19

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Answer 2

Answer:

Sum of the first n term of an AP is,

Sn = n²

S1 = 1² = 1

S2 = 2² = 4

S3 = 3² = 9

S4 = 4² = 16

…. and so on

Now, first term T1=S1 = a = 1

Next few terms,

T2 = S2-S1 = 4–1 =3

T3 = S3-S2 = 9–4 =5

T4 = S4-S3 = 16–9 = 7

…. and so on

Common difference d = 5–3 =7–5= 2

nth term of AP is, Tn = a+(n-1)d

For 10 th term, n=10

T10 = 1+(10–1) 2 = 19

Ans: 10th term is 19