the sum of first n term of AP is given by SN = 2n^2+ 3n and find the 16 term of AP
Answers
Answered by
7
hello Frnd
Given as
To find out we need to find first term and Common difference
Let n= 1
We got the first term a = 5
Now also put n=2
Since it's the sum of 2 terms
That's why
2nd term = S2 - a
= 14 - 5
= 9
Now we have
a1 = 5 and a2 = 9
Now d = a2- a1
d = 9 - 5 = 4
Now 16th term
hope it helps
jerri
Given as
To find out we need to find first term and Common difference
Let n= 1
We got the first term a = 5
Now also put n=2
Since it's the sum of 2 terms
That's why
2nd term = S2 - a
= 14 - 5
= 9
Now we have
a1 = 5 and a2 = 9
Now d = a2- a1
d = 9 - 5 = 4
Now 16th term
hope it helps
jerri
Answered by
1
hello,
akarsh here,
ur solution is,
.
.
.
s(n)=2n²+3n. (given)
first,
put the value of n =1
s(1)=2+3
=5
=a(first term)
.
.
.now,
put n=2......
s(2)=8+6
=14
.
to find a2(second term)
a2=s2-s1
=14-5
=9
.
.
d(common difference)=a2-a1
=9-5
=4
now,
a=5,d=4
.
.
.
therefore,
a(n)=a+(n-1)d
a(16)=5+(16-1)4
=60+5
=65
THEREFORE, 16TH TERM IS 65
.
.
.thank you
akarsh here,
ur solution is,
.
.
.
s(n)=2n²+3n. (given)
first,
put the value of n =1
s(1)=2+3
=5
=a(first term)
.
.
.now,
put n=2......
s(2)=8+6
=14
.
to find a2(second term)
a2=s2-s1
=14-5
=9
.
.
d(common difference)=a2-a1
=9-5
=4
now,
a=5,d=4
.
.
.
therefore,
a(n)=a+(n-1)d
a(16)=5+(16-1)4
=60+5
=65
THEREFORE, 16TH TERM IS 65
.
.
.thank you
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