the sum of first n terms ap sn,is 3n2+6n.find the nth term of ap.
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Sn=3n2+6n
S1=3 (1)2+6 (1)
S1=a1=15
S2=3 (2)2+6 (2)
S2=48
a2=S2-s1
=48-15
=33
d=a2-a1
= 33-15
=18
an=a+(n-1)d
S1=3 (1)2+6 (1)
S1=a1=15
S2=3 (2)2+6 (2)
S2=48
a2=S2-s1
=48-15
=33
d=a2-a1
= 33-15
=18
an=a+(n-1)d
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