the sum of first n terms of a A.P is n/2(3n+13). find its 30th term
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t30 = 30 /2(3×30+13)
= 30/ 2(90+13)
= 30/2(103)
= 30 / 206
= 15/103
30th term is 15/103
= 30/ 2(90+13)
= 30/2(103)
= 30 / 206
= 15/103
30th term is 15/103
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