the sum of first n terms of an A. P. is.
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Sn= n/2 [2a+(n-1)d]
where,
n= total number of terms
a= starting term
d= common difference between each term
Example,
1,3,5,7,9,11,13,15
in the list og A.P. given above,find the sum of those numbers?
Answer-
Total terms = n = 8
starting term = a = 1
common difference between each term = 2
Therefore,
On applying formula of sum of A.P.
Sn= n/2[2a+(n-1)d]
= 8/2[2×1 + (8-1)2]
=4[2 + 14]
=4×16
=64
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