Question

the sum of first n terms of an A.P is 33n2 +4n. find the 25th term of this A.P

Answer 1

Answer :

Given that the sum of the first n terms of the AP,

Sn = 33n² + 4n

Now, the sum of the first 25 terms of the AP,

S25 = (33 × 25²) + (4 × 25)

= 20725

and the sum of the first 24 terms of the AP,

S24 = (33 × 24²) + (4 × 24)

= 19104

∴ the 25th term of the AP be

t25

= S25 - S24

= 20725 - 19104

= 1621

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