The sum of first n terms of an A.P. is 3n2 + 4n. Find the 25th term of thisAP
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3
Answer:
We
Step-by-step explanation:we have ,
Sn=3n^2 +4n and S1=3+4=7
Therefore S25=3×(25)^2+4×25=1975
Therefore first term 7
Now
S25=1975
25/2×(7+L) =1975
7+L=158
There fore last term = 151
Answered by
0
Answer:
25th term = 151
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