The sum of first n terms of an A.P. is given by Sn=3n²+4n, determine the A.P. and it's 12th term.
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given that sn= 3n²+4n
- now first term will be
- a1= 7
- And sum of two term will be 12+8=20
- now a2= 20-7= 13
- so d= 6
- now 12 th term is ... a12 = 7+11×6 = 73
hence A12= 73
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