The sum of first n terms of an A.P.is n/2(3n+13) find the 30th term
Answers
Answered by
32
n/2(3n+13) is the general term for the ap so, we can put the value of n in any case for this ap and get the answer
in this case,
n=30 so,
=30/2[(30)(3)+13]
=15(90+13)
=103*15
=1545
thus the 30th term of this AP is 1545
Hope my answer helps
PLEASE MARK AS BRAINLIEST !!! ^_^
in this case,
n=30 so,
=30/2[(30)(3)+13]
=15(90+13)
=103*15
=1545
thus the 30th term of this AP is 1545
Hope my answer helps
PLEASE MARK AS BRAINLIEST !!! ^_^
Similar questions