The sum of first n terms of an ap is 3nsqure + 6n. find the nth term of this ap
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n/2(2a+( n-1)d )=3nsquare + 6n
2a +( n-1)d = 6n +12
2a + nd-d =6n +12
nd - 6n=12+d - 2a
n(d-6)=12+d-2a
n=12+d-2a/d-6
2a +( n-1)d = 6n +12
2a + nd-d =6n +12
nd - 6n=12+d - 2a
n(d-6)=12+d-2a
n=12+d-2a/d-6
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