Question

The sum of first 'n' terms of an ap is
(4 n²+2n). The nth term of this AP is? ​

Answer 1

Answer:

8n-2 answer

Step-by-step explanation:

Sn=4n²+2n (given,)

Sn=n/2{2a+(n-1)d}

n/2{2a+(n-1)d}=4n²+2n

n/2{2a+(n-1)d}=n(4n+2)

1/2{2a+(n-1)d}=(4n+2)

2a+(n-1)d=8n+4

2a+nd-d=8n+4

(2a-d)+nd=8n+4

by seperating

nd=8n & (2a-d)=4

d=8 & 2a-8=4

a=6

tn=a+(n-1)d

=6+(n-1)8

=6+8n-8

=8n-2 answer