The sum of first n terms of an AP is given by 2
n S = 2n + 3n . Find the sixteenth term of
the AP.
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16 th term of an ap =sum of 16 terms -sum of 15 terms
t16 =2(16) +3 (16) - {2 (15) +3 (15)}
= 32+48-{30+45)
= 80 - 75=5
t16 =2(16) +3 (16) - {2 (15) +3 (15)}
= 32+48-{30+45)
= 80 - 75=5
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