The sum of first n terms of an AP is given by Sn = 2n^2 + 3n. Find the sixteenth term of the AP
varrxx:
First find s15 & s16.After that subtract s15 from s16
Answers
Answered by
1
Sn=2n²+3n
Let
S1=2×1²+3×1=5
S2=2×2²+3×2=14
S3=2×3²+3×3=27
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S16=n/2{2a+(n-1)d}
=>S16=8{2×5+15×9}
=>S16=8{145}
=>S16=1160
Let
S1=2×1²+3×1=5
S2=2×2²+3×2=14
S3=2×3²+3×3=27
..................................
..................................
S16=n/2{2a+(n-1)d}
=>S16=8{2×5+15×9}
=>S16=8{145}
=>S16=1160
Answered by
1
Sn = 2n2 + 3n
S1 = 5 = a1
S2 = a1 + a2 = 14
a2 = 9
d = a2 – a1 = 4
a16 = a1 + 15d
a16 = 5 + 15(4) = 65
S1 = 5 = a1
S2 = a1 + a2 = 14
a2 = 9
d = a2 – a1 = 4
a16 = a1 + 15d
a16 = 5 + 15(4) = 65
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