The sum of first n terms of an AP is given by Sn=2n sq+3n.Find the sixteenth term of the AP.
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Sn = 2n^2+3n
S1 = 2+3=5
S2= 8+6=14
So a1= 5
a2 = S2-S1 = 14-5=9
So d= 9-5 = 4
A16 = a+15d= 5+4(15)=5+60=65
S1 = 2+3=5
S2= 8+6=14
So a1= 5
a2 = S2-S1 = 14-5=9
So d= 9-5 = 4
A16 = a+15d= 5+4(15)=5+60=65
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