The sum of first n terms of an AP is given by Sn = 2n2
+ 3n . Find the sixteenth term of the AP.
Answers
Answered by
1
Given Sn = 2n^2 + 3n
S16 = 2×16×16 +3×16
= 512 + 48
= 5 6 0
S16 = 2×15×15+3×15
= 2×225 + 45
= 4 50 + 45
= 495
S16 = S16 - S 15
= 560 - 495
= 4 65
S16 = 2×16×16 +3×16
= 512 + 48
= 5 6 0
S16 = 2×15×15+3×15
= 2×225 + 45
= 4 50 + 45
= 495
S16 = S16 - S 15
= 560 - 495
= 4 65
Answered by
4
Answer: 65
Step-by-step explanation:
Sn = 2n^2 + 3n
S1 = 5 = a1
S2 = a1 + a2 = 14
⇒ a2 = 9
d = a2 - a1= 4
a16 = a1 + 15d
= 5 + 15(4)
= 65
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