The sum of first n terms of an AP is given by Sn = 3n+ 10n. Find the nth term of the AP
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Answer:
Sn = 3n^2 + 10n
So, S(n - 1) = 3 (n - 1)^2 + 3(n - 1)
So, An = Sn - S(n - 1) = 3n^2 + 10n - 3(n - 1)^2 - 10(n - 1) = 3n^2 + 10n - 3 ((n^2) - 2n + 1) -10(n - 1) = 3n^2 + 10n - 3n^2 + 6n - 3 - 10n + 10 = 6n + 7
So, n th term of the given sequence is (6n + 7), its first term is 13 and common difference is 6. The common difference is constant. So, the given sequence
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