The sum of first n terms of an AP is given by Sn= 4n^2+3n. Find the sixteenth term of the AP
Answers
Answered by
2
a=7;
t2=22;
d=22-7=15;
t16=a+15d;
7+15*15
=232
t2=22;
d=22-7=15;
t16=a+15d;
7+15*15
=232
Answered by
1
As we Ae given the sum of n terms of the AP, we know that the nth term will be =
Sum of n terms - sum of (n-1) terms
=> T(n) = S(n) - S(n-1)
=> T(16) = S(16) - S(15)
=> T(16) = 4(16²) + 3(16) - [ 4(15²) + 3(15)]
=> T(16) = 127
Hope it helped you :)
Sum of n terms - sum of (n-1) terms
=> T(n) = S(n) - S(n-1)
=> T(16) = S(16) - S(15)
=> T(16) = 4(16²) + 3(16) - [ 4(15²) + 3(15)]
=> T(16) = 127
Hope it helped you :)
Similar questions