The sum of first n terms of an AP is oppation (1). S=n/2{2a+(n+1)d}. (2). S=a+(n-1)d. (3). S=n{2a+(n-1)d} (4) . S=n/2{2a+(n-1)d}
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Answer:
4. n/2[2a + (n – 1)d]
it is the correct answer.
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(4) S=n/2{2a+(n-1)d
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