The sum of first n terms of an AP Sn=3n&3-4n, then its nth term is
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Answer:
Step-by-step explanation:
Given S
n
=5n
2
+3n
S
n−1
=5(n−1)
2
+3(n−1)
=5(n
2
−2n+1)+3n−3
=5n
2
−10n+3n+5−3
=5n
2
−7n+2
T
n
=S
n
−S
n−1
=5n
2
+3n−5n
2
+7n−2
=10n−2
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