The sum of first ‘n’ terms of an arithemetic progression is given by the formula
Sn
= 3n2 + n, then its 3rd term is
Answers
Answered by
1
Step-by-step explanation:
sn= 3n + n
s3 = 3(3) +3
s3 =9 +3
s3 = 12
Answered by
0
Answer:
The sum of first ‘n’ terms of an arithemetic progression is given by the formula
Sn
= 3n2 + n, then its 3rd term is
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