Math, asked by haleshkavitha81, 8 hours ago

The sum of first ‘n’ terms of an arithemetic progression is given by the formula

Sn

= 3n2 + n, then its 3rd term is

Answers

Answered by Anonymous

1

Step-by-step explanation:

sn= 3n + n

s3 = 3(3) +3

s3 =9 +3

s3 = 12

Answered by amarnathbadri17

0

Answer:

The sum of first ‘n’ terms of an arithemetic progression is given by the formula

Sn

= 3n2 + n, then its 3rd term is

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